sort algorithm in java
Bubble sort
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| public static void bubblesort(int[] array){
boolean sorted = false;
int temp;
while(!sorted){
sorted = true;
for(int i = 0; i < array.length - 1; i++){
if(array[i] > array[i+1]){
temp = array[i];
array[i] = array[i+1];
array[i+1] = temp;
sorted = false;
}
}
}
}
|
Insertion Sort
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| public static void insertionsort(int[] array){
for(int i =0; i < array.length; i++){
int current = array[i];
int j = i-1;
while(j >= 0; current < array[j]){
array[j+1] = array[j];
j--;
}
array[j+1] = current;
}
}
|
Selection Sort
Merge Sort
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| public static void merge(int[] left_arr,int[] right_arr, int[] arr,int left_size, int right_size){
int i=0,l=0,r = 0;
//The while loops check the conditions for merging
while(l<left_size && r<right_size){
if(left_arr[l]<right_arr[r]){
arr[i++] = left_arr[l++];
}
else{
arr[i++] = right_arr[r++];
}
}
while(l<left_size){
arr[i++] = left_arr[l++];
}
while(r<right_size){
arr[i++] = right_arr[r++];
}
}
public static void mergeSort(int [] arr, int len){
if (len < 2){return;}
int mid = len / 2;
int [] left_arr = new int[mid];
int [] right_arr = new int[len-mid];
//Dividing array into two and copying into two separate arrays
int k = 0;
for(int i = 0;i<len;++i){
if(i<mid){
left_arr[i] = arr[i];
}
else{
right_arr[k] = arr[i];
k = k+1;
}
}
// Recursively calling the function to divide the subarrays further
mergeSort(left_arr,mid);
mergeSort(right_arr,len-mid);
// Calling the merge method on each subdivision
merge(left_arr,right_arr,arr,mid,len-mid);
}
|
Quick Sort
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| public class Test {
public static void main(String[] args) {
int n[] = { 6, 5, 2, 7, 3, 9, 8, 4, 10, 1 };
quicksort(n);
System.out.print("快排结果:");
for (int m : n) {
System.out.print(m + " ");
}
}
public static void quicksort(int n[]) {
sort(n, 0, n.length - 1);
}
public static void sort(int n[], int l, int r) {
if (l < r) {
// 一趟快排,并返回交换后基数的下标
int index = patition(n, l, r);
// 递归排序基数左边的数组
sort(n, l, index - 1);
// 递归排序基数右边的数组
sort(n, index + 1, r);
}
}
public static int patition(int n[], int l, int r) {
// p为基数,即待排序数组的第一个数
int p = n[l];
int i = l;
int j = r;
while (i < j) {
// 从右往左找第一个小于基数的数
while (n[j] >= p && i < j) {
j--;
}
// 从左往右找第一个大于基数的数
while (n[i] <= p && i < j) {
i++;
}
// 找到后交换两个数
swap(n, i, j);
}
// 使划分好的数分布在基数两侧
swap(n, l, i);
return i;
}
private static void swap(int n[], int i, int j) {
int temp = n[i];
n[i] = n[j];
n[j] = temp;
}
}
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